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Volume and Measurement Conversion: math test solutions, Grade 5 – download the PDF

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Test solutions Grade 5 : Volume and Measurement Conversion — Zyro the alien explorer of Planète Maths

Test solutions with the detailed point scale. Add up your points and spot what to review.

Suggested time: 45 minutes. Out of 20 points. Calculator allowed only when the problem says so.

1 Conversions / 4 pts

  1. \(6 \times 3 = 18\), so 6 yd = 18 ft. (1 pt)
  2. \(64 \div 16 = 4\), so 64 oz = 4 lb. (1 pt)
  3. \(12 \div 2 = 6\), so 12 pt = 6 qt. (1 pt)
  4. \(2.4 \times 1{,}000 = 2{,}400\), so 2.4 km = 2,400 m. (1 pt)

2 Volume formula / 3 pts

  1. \(V = 9 \times 4 \times 5 = 36 \times 5 = 180\). The volume is 180 cm3. (1 pt)
  2. \(252 = 42 \times h\) (1 pt), so \(h = 252 \div 42 = 6\). The height is 6 in. (1 pt)

3 A composite solid / 4 pts

  1. Tall part: \(2 \times 3 \times 4 = 24\) cm3 (1 pt). Low part: \(6 \times 3 \times 2 = 36\) cm3 (1 pt). Total: \(24 + 36 = 60\) cm3. (1 pt)
  2. Full block: \(8 \times 3 \times 4 = 96\). Missing piece: \(6 \times 3 \times 2 = 36\). \(96 - 36 = 60\) cm3, the same result. (1 pt)

4 The sandbox / 3 pts

  1. \(V = 8 \times 6 \times 2 = 96\) ft3. (1 pt)
  2. \(96 \div 4 = 24\) (1 pt). 24 bags are needed. (1 pt)

5 Ribbons on a line plot / 3 pts

  1. The pieces of \(1\dfrac{1}{4}\) ft and \(1\dfrac{1}{2}\) ft are longer than 1 ft: 2 pieces. (1 pt)
  2. Total: \(\dfrac{2+3+4+4+5+6}{4} = \dfrac{24}{4} = 6\) ft. (1 pt) Then \(6 \div 6 = 1\): each piece is 1 ft long. (1 pt)

6 A fish tank / 3 pts

  1. \(V = 30 \times 20 \times 25 = 600 \times 25 = 15{,}000\) cm3. (1 pt)
  2. 15,000 mL = 15 L. (1 pt)
  3. \(15 - 12 = 3\) L, which is 3,000 mL. (1 pt)
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