
Written solutions to the chapter problems. Check each step, then correct yourself.
1 Lunch combinations ★★★
Three stages, so we multiply: \(5\times4\times3=60\).
Answer: 60 different lunches.
2 Factorial arithmetic ★★★
\(6!=720\).
\(\dfrac{8!}{6!}=8\times7=56\).
\(P(7,2)=7\times6=42\).
\(C(7,2)=\dfrac{42}{2!}=21\).
3 Bike lock ★★★
(a) \(10\times10\times10\times10=10{,}000\).
(b) \(10\times9\times8\times7=5{,}040\).
4 Pizza toppings ★★★
Order does not matter (the same toppings give the same pizza), so we use a combination: \(C(9,3)=\dfrac{9\times8\times7}{3\times2\times1}=84\).
Answer: 84 pizzas.
5 Coin and die ★★★
The coin and the die do not influence each other, so the events are independent: \(\dfrac12\times\dfrac36=\dfrac14\).
Answer: \(\dfrac14=0.25\).
6 Tea or coffee ★★★
(a) There are \(9+21=30\) people under 30: \(P=\dfrac{21}{30}=0.7\).
(b) There are \(11+19=30\) people 30 or older: \(P=\dfrac{11}{30}\approx0.367\).
7 Heights and the empirical rule ★★★
(a) \(66\pm3\): between 63 and 69 inches.
(b) \(66\pm6\): between 60 and 72 inches.
(c) 72 inches is 2 standard deviations above the mean. About 95% lie within, so the two tails share 5%, and the upper tail is about \(2.5\%\).
8 Books on a shelf ★★★
Glue the two books into one block. Then we arrange 4 objects: \(4!=24\) ways. Inside the block the two books can be swapped: \(2!=2\) ways.
Total: \(24\times2=48\).
9 Choosing a committee ★★★
Choose the girls: \(C(4,2)=6\). Choose the boys: \(C(5,2)=10\). Multiply the two stages: \(6\times10=60\).
10 Two aces ★★★
The draws are dependent: \(\dfrac4{52}\times\dfrac3{51}=\dfrac{12}{2652}=\dfrac1{221}\).
Answer: \(\dfrac{1}{221}\approx0.0045\).
11 Exactly one red ★★★
Two ways: red then green, or green then red.
\(\dfrac6{10}\times\dfrac49+\dfrac4{10}\times\dfrac69=\dfrac{24}{90}+\dfrac{24}{90}=\dfrac{48}{90}=\dfrac8{15}\).
12 Guessing on a quiz ★★★
Binomial with \(n=8\), \(p=0.5\): \(P(X=6)=C(8,6)(0.5)^6(0.5)^2=\dfrac{28}{256}=\dfrac7{64}\approx0.109\).
13 Expanding a binomial ★★★
Row 4 of Pascal’s triangle: \(1,4,6,4,1\). Powers of \(-3\): \(1,-3,9,-27,81\).
\((x-3)^4=x^4-12x^3+54x^2-108x+81\).
14 Standard deviation by hand ★★★
Mean: \(\dfrac{32}{8}=4\).
Squared deviations: \(9,1,1,1,0,0,4,16\), sum \(32\).
\(\sigma=\sqrt{32/8}=\sqrt4=2\).
15 Which test was better? ★★★
Maya: \(z=\dfrac{82-70}{8}=1.5\).
Brother: \(z=\dfrac{31-25}{3}=2\).
His score is 2 standard deviations above the mean, Maya’s is 1.5. Relative to his class, the brother did better.
16 Stratified sample ★★★
Total: \(240+220+200+140=800\), so the sampling fraction is \(\dfrac{80}{800}=10\%\).
9th: 24; 10th: 22; 11th: 20; 12th: 14. Check: \(24+22+20+14=80\).
17 Letters of STATISTICS ★★★
There are 10 letters: S three times, T three times, I twice, A once, C once.
\(\dfrac{10!}{3!\,3!\,2!}=\dfrac{3{,}628{,}800}{72}=50{,}400\).
18 A screening test ★★★
Sick: \(0.02\times1000=20\) people, of whom \(0.9\times20=18\) test positive.
Healthy: 980 people, of whom \(0.05\times980=49\) test positive.
\(P(\text{sick}\mid\text{positive})=\dfrac{18}{18+49}=\dfrac{18}{67}\approx0.269\).
Only about 27%: because the condition is rare, most positives are false alarms.
19 Defective parts ★★★
(a) Complement: \(1-0.9^{10}\approx1-0.3487=0.6513\).
(b) \(C(10,2)(0.1)^2(0.9)^8=45\times0.01\times0.4305\approx0.1937\).
(c) Mean \(=10\times0.1=1\). Standard deviation \(=\sqrt{10\times0.1\times0.9}=\sqrt{0.9}\approx0.949\).
20 Coefficients ★★★
(a) The term with \(x^3\) is \(C(6,3)(2x)^3(1)^3=20\times8x^3=160x^3\). The coefficient is 160.
(b) Replace \(x\) by 1: \((2+1)^6=3^6=729\).
21 Polling margin of error ★★★
(a) \(\sqrt{\dfrac{0.64\times0.36}{625}}=\dfrac{0.48}{25}=0.0192\), so \(ME=1.96\times0.0192\approx0.0376\), about 3.8%.
(b) \(0.64\pm0.0376\): from about 60.2% to 67.8%.
(c) \(1.96\times\dfrac{0.5}{\sqrt n}\le0.03\) gives \(\sqrt n\ge32.67\), so \(n\ge1067.1\). A sample of 1,068 residents is needed.
22 Battery life ★★★
(a) 30 and 50 are \(\mu\pm2\sigma\): about 95%.
(b) 45 is \(\mu+\sigma\). Outside \(\pm\sigma\) lies 32%, half of it above: about 16%.
(c) From \(-1\sigma\) to \(+2\sigma\): \(34\%+47.5\%=81.5\%\). Then \(0.815\times2500=2037.5\), about 2,038 batteries.
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