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Equations and Inequalities: practice solutions, Grade 6 – download the PDF

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Practice solutions Grade 6 : Equations and Inequalities — Zyro the alien explorer of Planète Maths

Written solutions to the chapter problems. Check each step, then correct yourself.

2 Adding and subtracting ★★★

  1. Subtract 7: \(x = 19 - 7 = 12\).
  2. Subtract 2.5: \(y = 6 - 2.5 = 3.5\).
  3. Subtract 9: \(m = 14 - 9 = 5\).

Check: \(12 + 7 = 19\), \(3.5 + 2.5 = 6\), \(5 + 9 = 14\).

3 Multiplying and dividing ★★★

  1. Add 8: \(n = 19\).
  2. Divide by 6: \(p = 9\).
  3. Multiply by 5: \(k = 35\).
  4. Divide by 0.5: \(w = 12\).

Check: \(19 - 8 = 11\); \(6 \times 9 = 54\); \(35 \div 5 = 7\); \(0.5 \times 12 = 6\).

4 Choose the inverse operation ★★★

  1. Subtract 12: \(x = 18\).
  2. Add 3: \(x = 13\).
  3. Divide by 8: \(x = 5\).
  4. Multiply by 6: \(x = 12\).

5 From words to equations ★★★

  1. \(n - 7 = 20\), so \(n = 27\).
  2. \(3n = 36\), so \(n = 12\).
  3. \(\dfrac{n}{4} = 9\), so \(n = 36\).
  4. \(n + 12 = 31\), so \(n = 19\).

6 Reading a number line ★★★

  1. The circle is open at 5 and the ray goes right: \(x > 5\).
  2. 6 and 9 are solutions. 4 is too small, and 5 is not included because the circle is open.

7 Test the numbers ★★★

  1. Only numbers strictly greater than 6: 9 and 12.
  2. Numbers less than or equal to 6: 3 and 6.

Notice that 6 is a solution of (b) but not of (a).

8 Stickers ★★★

Let \(s\) be the number of stickers at first. Equation: \(s + 17 = 45\). Subtract 17: \(s = 28\).

Check: \(28 + 17 = 45\). Maya had 28 stickers.

9 Concert tickets ★★★

Equation: \(6t = 45\). Divide both sides by 6: \(t = 7.5\).

Check: \(6 \times 7.5 = 45\). One ticket costs $7.50.

10 A weekend hike ★★★

Equation: \(d + 3.5 = 9.2\). Subtract 3.5: \(d = 5.7\).

Check: \(5.7 + 3.5 = 9.2\). Leo hiked 5.7 miles on Saturday (about 9.2 km).

11 Fractions and decimals ★★★

  1. Subtract \(\dfrac{1}{4}\): \(x = \dfrac{3}{4} - \dfrac{1}{4} = \dfrac{2}{4} = \dfrac{1}{2}\).
  2. Add \(\dfrac{2}{3}\): \(y = \dfrac{1}{3} + \dfrac{2}{3} = 1\).
  3. Divide by 0.4: \(x = 2.8 \div 0.4 = 7\).

12 Find the mistake ★★★

Sam added 9 to 21, but the equation already adds 9 to \(x\). He must use the inverse operation, subtraction.

Correct work: \(x = 21 - 9 = 12\). Check: \(12 + 9 = 21\).

13 Solve the inequalities ★★★

  1. Subtract 5: \(x > 7\).
  2. Add 3: \(y \leq 12\).
  3. Divide by 4: \(n < 7\).
  4. Multiply by 3: \(m \geq 18\).

14 Graph an inequality ★★★

The symbol \(\geq\) includes 3, so the circle is closed. The ray goes to the right.

012345678x ≥ 3

15 The elevator ★★★

Total weight must be at most 1,200: \(640 + w \leq 1200\). Subtract 640: \(w \leq 560\).

They can add at most 560 pounds (about 254 kg).

16 Counting solutions ★★★

Whole numbers start at 0. The whole numbers less than 5 are 0, 1, 2, 3 and 4: that is five solutions, so Tom is wrong. (Numbers like 4.9 are solutions too, but they are not whole numbers.)

17 The garden rectangle ★★★

  1. Area = length times width: \(7l = 91\). Divide by 7: \(l = 13\) cm.
  2. Perimeter \(= 2 \times (13 + 7) = 2 \times 20 = 40\) cm.

Check: \(7 \times 13 = 91\).

18 Sharing a bill ★★★

  1. \(9x = 135\).
  2. Divide by 9: \(x = 15\). Each pays $15.
  3. With 8 friends: \(8y = 135\), so \(y = 16.875\), about $16.88. That is about $1.88 more each ($16.875 - 15 = 1.875).

19 Tall enough to ride ★★★

  1. \(44.5 + g \geq 48\). Subtract 44.5: \(g \geq 3.5\).
  2. No: \(3 < 3.5\), so she would be 47.5 inches, still too short.

20 Two conditions at once ★★★

First: subtract 4, so \(x < 7\). Second: divide by 3, so \(x > 4\).

Whole numbers greater than 4 and less than 7: 5 and 6. Check 6: \(6 + 4 = 10 < 11\) and \(18 > 12\).

21 Saving for a bike ★★★

  1. \(64 + s \geq 150\), so \(s \geq 86\).
  2. \(9w \geq 86\), so \(w \geq \dfrac{86}{9} \approx 9.56\).
  3. Weeks are counted in whole numbers: 9 weeks give $81, which is not enough; 10 weeks give $90, which is enough.

22 Error in an inequality ★★★

Jo subtracted 5, but 5 multiplies \(x\). The inverse operation is division: \(x \leq 40 \div 5 = 8\).

Inside: \(x = 6\) gives \(30 \leq 40\), true. Outside: \(x = 9\) gives \(45 \leq 40\), false. With Jo’s answer, \(x = 30\) would be allowed but \(5 \times 30 = 150\) is far too big.

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