
Written solutions to the chapter problems. Check each step, then correct yourself.
1 Complement and supplement ★★★
Complement: \(90-38=52\), so \(52^\circ\).
Supplement: \(180-38=142\), so \(142^\circ\).
The complement of \(38^\circ\) is \(52^\circ\) and its supplement is \(142^\circ\).
2 Sorting pairs ★★★
- \(18+72=90\): complementary.
- \(110+70=180\): supplementary.
- \(44+47=91\): neither.
- \(120+60=180\): supplementary.
3 Crossing lines ★★★
Angle \(b\) is vertical to the \(72^\circ\) angle, so \(b=72^\circ\).
Angle \(a\) forms a linear pair with the \(72^\circ\) angle: \(a=180-72=108^\circ\).
Angle \(c\) is vertical to \(a\), so \(c=108^\circ\).
Answer: \(a=108^\circ\), \(b=72^\circ\), \(c=108^\circ\).
4 Can it be a triangle? ★★★
- \(5+6=11>10\): yes.
- \(2+3=5<7\): no.
- \(8+8=16>15\): yes.
- \(4+9=13\), which is not greater than 13: no, the triangle would be flat.
5 Name the cross section ★★★
- A square, the same size as the face.
- A circle.
- A circle.
- A triangle.
6 Angles on a line ★★★
Angles on a straight line add up to \(180^\circ\).
\(40+75+x=180\), so \(115+x=180\) and \(x=65\).
The angle \(x\) measures \(65^\circ\).
7 The leaning ladder ★★★
The wall and the ground meet at \(90^\circ\), so the two angles of the ladder are complementary.
\(90-74=16\).
The ladder makes a \(16^\circ\) angle with the wall.
8 A supplementary equation ★★★
\((x+14)+(2x-5)=180\), so \(3x+9=180\) and \(3x=171\), thus \(x=57\).
The angles are \(57+14=71\) and \(2(57)-5=109\), so \(71^\circ\) and \(109^\circ\).
Check: \(71+109=180\).
9 Vertical angles with variables ★★★
Vertical angles are equal: \(4x-7=2x+21\), so \(2x=28\) and \(x=14\).
The angle is \(4(14)-7=49\). Check: \(2(14)+21=49\).
Each angle measures \(49^\circ\).
10 One angle four times the other ★★★
Let the smaller angle be \(x\). Then \(x+4x=180\), so \(5x=180\) and \(x=36\).
The angles are \(36^\circ\) and \(4(36)=144^\circ\).
11 Twenty degrees more ★★★
Let the smaller angle be \(x\); the larger is \(x+20\). Then \(2x+20=90\), so \(x=35\).
The angles are \(35^\circ\) and \(55^\circ\).
Check: \(35+55=90\) and \(55-35=20\).
12 Range for the third side ★★★
\(s<9+14=23\) and \(s>14-9=5\), so \(5
The whole numbers are \(6, 7, \dots, 22\). That is \(22-6+1=17\) values.
13 Craft sticks ★★★
The third length must satisfy \(12-7
4 cm: no. 6 cm: yes. 18 cm: yes. 19 cm: no, because \(12+7=19\) is not greater than 19.
Dana can use 6 cm or 18 cm.
14 How many triangles? ★★★
- \(5+5=10<12\): no triangle.
- \(6+8=14>10\): exactly one triangle.
- The angles add up to \(180^\circ\) but no length is given: many triangles of different sizes.
- Two sides and the included angle: exactly one triangle.
15 Slicing a box ★★★
A cut parallel to a face gives a rectangle congruent to that face.
- \(10\times 6=60\text{ in}^2\).
- \(6\times 4=24\text{ in}^2\).
16 A linear pair in a crossing ★★★
The angles form a linear pair: \((2x+10)+(3x+20)=180\), so \(5x+30=180\) and \(x=30\).
The angles are \(2(30)+10=70\) and \(3(30)+20=110\). Check: \(70+110=180\).
The vertical angle of the first one is also \(70^\circ\).
17 Three angles on a line ★★★
The sum is \(180\): \((x+10)+(2x-15)+(3x+5)=180\), so \(6x=180\) and \(x=30\).
The angles are \(40^\circ\), \(2(30)-15=45^\circ\) and \(3(30)+5=95^\circ\).
Check: \(40+45+95=180\).
18 Complement and supplement together ★★★
Let the angle be \(a\). Then \(90-a=\dfrac{180-a}{4}\). Multiply by 4: \(360-4a=180-a\), so \(180=3a\) and \(a=60\).
Check: complement \(30^\circ\), supplement \(120^\circ\), and \(120\div 4=30\).
The angle measures \(60^\circ\).
19 Three times the complement ★★★
\(180-a=3(90-a)\), so \(180-a=270-3a\) and \(2a=90\), thus \(a=45\).
Check: supplement \(135^\circ\), complement \(45^\circ\), and \(3\times 45=135\).
The angle measures \(45^\circ\).
20 Sides with a variable ★★★
\(x+(x+3)>2x+1\) gives \(2x+3>2x+1\), which is always true.
\(x+(2x+1)>x+3\) gives \(3x+1>x+3\), so \(2x>2\) and \(x>1\).
\((x+3)+(2x+1)>x\) gives \(3x+4>x\), true for positive \(x\).
So \(x>1\); the smallest whole number is \(x=2\), with sides 2 cm, 5 cm and 5 cm. Check: \(2+5>5\).
21 Construction plan ★★★
- \(180-50-60=70\), so the third angle is \(70^\circ\).
- Draw \(AB=8\text{ cm}\). With the protractor centered on \(A\), mark \(50^\circ\) and draw a ray. Center it on \(B\), mark \(60^\circ\) from side \(BA\) and draw a ray. Point \(C\) is where the rays cross.
- Yes: two angles and the included side determine exactly one triangle.
22 Slicing a cone ★★★
Halfway up, the radius is \(5\div 2=2.5\text{ cm}\).
Area \(=\pi r^2=\pi(2.5)^2=6.25\pi\approx 19.6\text{ cm}^2\).
The cross section is a circle of radius 2.5 cm and area about 19.6 cm².
23 The garden fence ★★★
Triangle inequality: \(15-8
Fence limit: \(15+8+s\le 40\), so \(s\le 17\).
Therefore \(8\le s\le 17\), which gives \(17-8+1=10\) possible lengths.
Test yourself: quick challenge for Grade 7
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