
Some questions ask what a quantity approaches: the speed of a car at one exact instant, or the cost per item when a factory makes huge batches. Others ask how likely an event is, or how to summarize a pile of data. This chapter joins both worlds. You will study limits, count arrangements, compute probabilities with the binomial and normal models, and fit a line to real data.
1. Intuitive limits and one-sided limits
We write \( \lim_{x\to a} f(x) = L \) when the values \( f(x) \) get as close as we like to \( L \) as \( x \) gets close to \( a \) from both sides, with \( x \neq a \). The value \( f(a) \) itself does not matter, and it may not even exist.
Let \( f(x) = \dfrac{x^2-9}{x-3} \). We cannot plug in \( x=3 \) because that gives \( \tfrac{0}{0} \). Try nearby values: \( f(2.9)=5.9 \), \( f(2.99)=5.99 \), \( f(3.01)=6.01 \), \( f(3.1)=6.1 \). The outputs close in on 6. Algebra confirms it: for \( x\neq 3 \), \( f(x)=\dfrac{(x-3)(x+3)}{x-3}=x+3 \), so \( \lim_{x\to 3} f(x)=6 \).
- Try direct substitution. If you get a real number, that is the limit (for a polynomial or a nice rational function).
- If you get \( \tfrac{0}{0} \), factor, simplify, or multiply by a conjugate, then substitute again.
- If the function changes formula at \( a \), look at each side separately.
\( \lim_{x\to a^-} f(x) \) is the value approached when \( x \) comes from the left (\( x \lt a \)). \( \lim_{x\to a^+} f(x) \) is the value approached from the right (\( x \gt a \)).
\( \lim_{x\to a} f(x) \) exists if and only if both one-sided limits exist and are equal.
Let \( f(x)=\begin{cases} 2x-1 & \text{if } x\lt 1\\ x^2+2 & \text{if } x\ge 1\end{cases} \). From the left, \( \lim_{x\to1^-} f(x)=2(1)-1=1 \). From the right, \( \lim_{x\to1^+} f(x)=1^2+2=3 \). Since \( 1\neq 3 \), the limit at \( x=1 \) does not exist, even though \( f(1)=3 \).
2. Limits at infinity
Here we ask what happens to \( f(x) \) as \( x \) grows without bound. We write \( \lim_{x\to\infty} f(x)=L \) when the graph levels off at the height \( L \); the line \( y=L \) is a horizontal asymptote. Remember that \( \tfrac{1}{x} \), \( \tfrac{1}{x^2} \), and similar terms shrink to 0.
For \( f(x)=\dfrac{a_n x^n+\cdots}{b_m x^m+\cdots} \): if \( n\lt m \) the limit is 0; if \( n=m \) the limit is \( \dfrac{a_n}{b_m} \); if \( n\gt m \) there is no finite limit (the values grow without bound).
For \( \lim_{x\to\infty}\dfrac{6x^2-5x}{2x^2+7} \), divide every term by \( x^2 \): \( \dfrac{6-\frac{5}{x}}{2+\frac{7}{x^2}}\to \dfrac{6}{2}=3 \). The line \( y=3 \) is a horizontal asymptote.
The graph above shows \( f(x)=\dfrac{2x+1}{x-1} \). Its horizontal asymptote is \( y=2 \) because the degrees match and \( \tfrac{2}{1}=2 \). It also has a vertical asymptote at \( x=1 \), where the denominator is 0 and the numerator is not.
\( \infty \) is not a number. Writing \( \lim_{x\to\infty} x^2=\infty \) only describes how the values behave; it does not mean the limit exists as a real number.
3. Permutations and combinations
To count outcomes, use the fundamental counting principle: if one choice can be made in \( m \) ways and a second in \( n \) ways, the two together can be made in \( m\cdot n \) ways. The factorial is \( n!=n(n-1)\cdots 2\cdot 1 \), with \( 0!=1 \).
A permutation is an arrangement where order matters: \( P(n,r)=\dfrac{n!}{(n-r)!} \). A combination is a selection where order does not matter: \( C(n,r)=\dfrac{n!}{r!\,(n-r)!} \). They are linked by \( P(n,r)=r!\cdot C(n,r) \).
Eight sprinters race for gold, silver, and bronze. Order matters: \( P(8,3)=8\cdot7\cdot6=336 \) podiums. A coach picks 4 of 10 students for a committee. Order does not matter: \( C(10,4)=\dfrac{10\cdot9\cdot8\cdot7}{4!}=210 \).
The word LEVEL has 5 letters, with L twice and E twice. The number of distinct arrangements is \( \dfrac{5!}{2!\,2!}=\dfrac{120}{4}=30 \).
Zyro asks: "If I swap two chosen items, do I get a different outcome?" If yes, use a permutation. If no, use a combination.
4. Conditional probability
The probability of \( A \) given that \( B \) has occurred is \( P(A\mid B)=\dfrac{P(A\cap B)}{P(B)} \), for \( P(B)\gt 0 \). Rearranged, it gives the multiplication rule \( P(A\cap B)=P(B)\cdot P(A\mid B) \). Events are independent when \( P(A\mid B)=P(A) \), that is, when \( P(A\cap B)=P(A)P(B) \).
Machine X makes 60% of a factory’s items and 2% of them are defective. Machine Y makes the other 40% and 5% of them are defective. Multiply along the branches of the tree:
Adding the two defective branches: \( P(D)=0.012+0.020=0.032 \). Now suppose an item is found defective. The chance it came from Y is \( P(Y\mid D)=\dfrac{0.020}{0.032}=0.625 \). So 62.5% of defective items come from Y, even though Y makes fewer items.
\( P(A\mid B) \) and \( P(B\mid A) \) are usually different. The chance that a defective item came from Y (0.625) is not the chance that a Y item is defective (0.05).
5. The binomial distribution
A random variable \( X \) is binomial when it counts successes in \( n \) trials that are independent, have only two outcomes, and share the same success probability \( p \).
\( P(X=k)=C(n,k)\,p^{k}(1-p)^{\,n-k} \) for \( k=0,1,\dots,n \). The mean is \( \mu=np \) and the standard deviation is \( \sigma=\sqrt{np(1-p)} \).
A player makes 40% of her shots and takes 5 independent shots. Then \( P(X=2)=C(5,2)(0.4)^2(0.6)^3=10\cdot0.16\cdot0.216=0.3456 \). The chance of at least one success is \( 1-P(X=0)=1-0.6^5=0.92224 \). The mean is \( 5\cdot0.4=2 \) shots and \( \sigma=\sqrt{5\cdot0.4\cdot0.6}=\sqrt{1.2}\approx1.10 \).
6. The normal distribution
Many measurements (heights, masses, test scores, manufacturing errors) pile up in a symmetric, bell-shaped curve centered at the mean \( \mu \). The spread is set by the standard deviation \( \sigma \), and the total area under the curve is 1.
In a normal distribution, about 68% of the values lie within \( 1\sigma \) of the mean, about 95% within \( 2\sigma \), and about 99.7% within \( 3\sigma \).
Apple masses are normal with \( \mu=150 \) g (about 5.3 oz) and \( \sigma=10 \) g. About 68% weigh between 140 g and 160 g, and about 95% between 130 g and 170 g. The fraction above 170 g is \( \dfrac{100\%-95\%}{2}=2.5\% \), because the curve is symmetric.
7. Standard deviation and z-scores
The standard deviation measures the typical distance between the data and their mean. For a whole population of \( n \) values, \( \sigma=\sqrt{\dfrac{\sum (x-\mu)^2}{n}} \). For a sample, divide by \( n-1 \) instead and write \( s \).
Data: 3, 5, 5, 7, 10, with mean \( \mu=6 \).
| \( x \) | \( x-\mu \) | \( (x-\mu)^2 \) |
|---|---|---|
| 3 | -3 | 9 |
| 5 | -1 | 1 |
| 5 | -1 | 1 |
| 7 | 1 | 1 |
| 10 | 4 | 16 |
The sum of squares is 28. Population: \( \sigma=\sqrt{28/5}=\sqrt{5.6}\approx2.37 \). Sample: \( s=\sqrt{28/4}=\sqrt7\approx2.65 \).
\( z=\dfrac{x-\mu}{\sigma} \) tells how many standard deviations a value lies above (\( z\gt0 \)) or below (\( z\lt0 \)) the mean. It lets you compare values from different scales.
Maya scored 84 on a test with \( \mu=72 \) and \( \sigma=8 \): \( z=\dfrac{84-72}{8}=1.5 \). Leo scored 93 on a test with \( \mu=80 \) and \( \sigma=10 \): \( z=1.3 \). Maya did better relative to her group.
8. Regression and correlation
When two quantities seem related, a scatter plot shows the pattern. The least-squares line \( \hat y=mx+b \) is the line that makes the sum of squared vertical gaps as small as possible. With means \( \bar x \), \( \bar y \):
\[ m=\dfrac{\sum (x-\bar x)(y-\bar y)}{\sum (x-\bar x)^2},\qquad b=\bar y-m\bar x. \]
The correlation coefficient \( r \), always between \( -1 \) and \( 1 \), measures how close the points are to a line: \( r \) near 1 is a strong positive trend, near \( -1 \) a strong negative trend, near 0 no linear trend.
After weeks of training \( x=1,2,3,4,5 \), an athlete does \( y=3,5,4,7,9 \) push-ups. Here \( \bar x=3 \), \( \bar y=5.6 \), \( \sum(x-\bar x)(y-\bar y)=14 \), \( \sum(x-\bar x)^2=10 \), and \( \sum(y-\bar y)^2=23.2 \). So \( m=1.4 \), \( b=5.6-1.4\cdot3=1.4 \), giving \( \hat y=1.4x+1.4 \), and \( r=\dfrac{14}{\sqrt{10\cdot23.2}}\approx0.92 \). Each extra week adds about 1.4 push-ups. At week 6 the model predicts \( 9.8 \).
A strong correlation does not prove that one variable causes the other. Also avoid extrapolation: predicting far outside the range of your data is unreliable.
Key takeaways
- A limit describes where \( f(x) \) is heading; it ignores the value at the point. A two-sided limit exists only if both one-sided limits agree.
- For rational functions at infinity, compare the degrees of numerator and denominator.
- Order matters: \( P(n,r)=\dfrac{n!}{(n-r)!} \). Order does not matter: \( C(n,r)=\dfrac{n!}{r!(n-r)!} \).
- \( P(A\mid B)=\dfrac{P(A\cap B)}{P(B)} \); a tree diagram multiplies along branches and adds across branches.
- Binomial: \( P(X=k)=C(n,k)p^k(1-p)^{n-k} \), \( \mu=np \), \( \sigma=\sqrt{np(1-p)} \).
- Normal data: about 68%, 95%, and 99.7% lie within 1, 2, and 3 standard deviations; \( z=\dfrac{x-\mu}{\sigma} \).
- The least-squares line has \( m=\dfrac{\sum(x-\bar x)(y-\bar y)}{\sum(x-\bar x)^2} \); \( r \) near \( \pm1 \) means a strong linear trend, but never proves causation.
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