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Multiplying Multi-Digit Whole Numbers: practice solutions, Grade 4 – download the PDF

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Practice solutions Grade 4 : Multiplying Multi-Digit Whole Numbers — Zyro the alien explorer of Planète Maths

Written solutions to the chapter problems. Check each step, then correct yourself.

2 Missing factors ★★★

  1. \(7 \times 7 = 49\), so the missing number is 70.
  2. \(6 \times 6 = 36\), so the missing number is 6.
  3. \(5 \times 9 = 45\), so the missing number is 9,000.
  4. \(8 \times 8 = 64\), so the missing number is 8.

3 Complete the area model ★★★

Split \(15 = 10 + 5\) and \(12 = 10 + 2\).

1051010 × 101005 × 1050210 × 2205 × 210Total = 180

\(100 + 20 + 50 + 10 = 180\). So \(15 \times 12 = 180\).

4 Expanded form ★★★

\(2{,}314 = 2{,}000 + 300 + 10 + 4\).

\(2{,}000 \times 3 = 6{,}000\), \(300 \times 3 = 900\), \(10 \times 3 = 30\), \(4 \times 3 = 12\).

\(6{,}000 + 900 + 30 + 12 = 6{,}942\). The product is 6,942.

5 True or false? ★★★

  1. False. \(4 \times 3 = 12\), but there is one more zero: \(4 \times 30 = 120\).
  2. True. \(6 \times 5 = 30\) and two zeros give 3,000.
  3. False. \(2 \times 2 = 4\) and two zeros give \(20 \times 20 = 400\). The sum \(20 + 20\) is 40, but the product is much greater.
  4. True. \(3 \times 7 = 21\) and three zeros give 21,000.

6 Muffins at the bakery ★★★

\(60 \times 8 = 6 \times 8\) tens \(= 48\) tens \(= 480\).

There are 480 muffins on 8 trays.

7 Name the property ★★★

  1. Commutative property: the order changes.
  2. Associative property: the grouping changes.
  3. Distributive property: 13 is split into \(10 + 3\).
  4. Identity property: multiplying by 1 does not change the number.
  5. Zero property: any number times 0 is 0.

8 4-digit times 1-digit ★★★

  1. \(1{,}000 \times 5 = 5{,}000\), \(200 \times 5 = 1{,}000\), \(30 \times 5 = 150\), \(8 \times 5 = 40\). The sum is \(5{,}000 + 1{,}000 + 150 + 40 = 6{,}190\).
  2. \(7{,}000 \times 6 = 42{,}000\), \(0 \times 6 = 0\), \(50 \times 6 = 300\), \(2 \times 6 = 12\). The sum is \(42{,}000 + 300 + 12 = 42{,}312\).

9 Two 2-digit numbers ★★★

\(34 \times 20 = 680\) and \(34 \times 6 = 204\).

\(680 + 204 = 884\). So \(34 \times 26 = 884\).

10 Area model for 42 times 31 ★★★

Split \(42 = 40 + 2\) and \(31 = 30 + 1\).

4023040 × 301,2002 × 3060140 × 1402 × 12Total = 1,302

\(1{,}200 + 40 + 60 + 2 = 1{,}302\). So \(42 \times 31 = 1{,}302\).

11 Estimate first ★★★

  1. Estimate: \(60 \times 30 = 1{,}800\). Exact: \(63 \times 28 = 63 \times 20 + 63 \times 8 = 1{,}260 + 504 = 1{,}764\). The exact answer is close to the estimate.
  2. Estimate: \(6{,}000 \times 4 = 24{,}000\). Exact: \(5{,}000 \times 4 + 900 \times 4 + 10 \times 4 + 7 \times 4 = 20{,}000 + 3{,}600 + 40 + 28 = 23{,}668\). It is a little less than the estimate because 5,917 was rounded up.

12 Find the mistake ★★★

Check with an estimate: \(3{,}000 \times 4 = 12{,}000\) and \(3{,}205\) is more than 3,000, so the product should be more than 12,000 by at least 800 or so.

Partial products: \(3{,}000 \times 4 = 12{,}000\), \(200 \times 4 = 800\), \(0 \times 4 = 0\), \(5 \times 4 = 20\). Total: \(12{,}000 + 800 + 20 = 12{,}820\).

Mia forgot the 800 from the hundreds place. The correct product is 12,820.

13 Seats in the stadium ★★★

\(48 \times 65 = 48 \times 60 + 48 \times 5 = 2{,}880 + 240 = 3{,}120\).

The section has 3,120 seats.

14 Mental math with properties ★★★

  1. \(7 \times 98 = 7 \times 100 - 7 \times 2 = 700 - 14 = 686\).
  2. \(6 \times 102 = 6 \times 100 + 6 \times 2 = 600 + 12 = 612\).
  3. \(25 \times 12 = 25 \times 4 \times 3 = 100 \times 3 = 300\).

15 Farm stand sales ★★★

Apples: \(36 \times 14 = 360 + 144 = 504\), so 504 dollars.

Pears: \(27 \times 18 = 270 \times 2 - 27 \times 2 = 540 - 54 = 486\), so 486 dollars.

Total: \(504 + 486 = 990\). The stand earns $990.

16 Cargo ship ★★★

  1. \(2{,}000 \times 7 = 14{,}000\), \(400 \times 7 = 2{,}800\), \(60 \times 7 = 420\), \(8 \times 7 = 56\). Sum: \(14{,}000 + 2{,}800 + 420 + 56 = 17{,}276\) containers.
  2. \(20{,}000 - 17{,}276 = 2{,}724\). The company still needs to move 2,724 containers.

17 The missing digit ★★★

Try the possible numbers. \(40 \times 23 = 920\), which is too small. \(45 \times 23 = 1{,}035\), still too small. \(46 \times 23 = 46 \times 20 + 46 \times 3 = 920 + 138 = 1{,}058\).

The hidden digit is 6, and the number is 46.

18 Which is greater? ★★★

\(35 \times 48 = 35 \times 50 - 35 \times 2 = 1{,}750 - 70 = 1{,}680\).

\(36 \times 47 = 36 \times 50 - 36 \times 3 = 1{,}800 - 108 = 1{,}692\).

\(36 \times 47\) is greater by \(1{,}692 - 1{,}680 = 12\).

19 Fundraiser goal ★★★

  1. \(80 \times 60 = 4{,}800\), so about 4,800 dollars.
  2. \(78 \times 62 = 78 \times 60 + 78 \times 2 = 4{,}680 + 156 = 4{,}836\) dollars.
  3. No, because \(4{,}836 < 5{,}000\). The band is missing \(5{,}000 - 4{,}836 = 164\) dollars.

20 Garden area ★★★

  1. \(85 \times 27 = 85 \times 20 + 85 \times 7 = 1{,}700 + 595 = 2{,}295\). The area is 2,295 square feet.
  2. The length is \(3 \times 85 = 255\) feet. The area is \(255 \times 27 = 5{,}100 + 1{,}785 = 6{,}885\) square feet. This is also \(3 \times 2{,}295\), so the answer makes sense.

21 Greatest product ★★★

Put the two greatest digits, 5 and 4, in the tens places. Then try the ones digits: \(52 \times 43 = 2{,}236\) and \(53 \times 42 = 2{,}226\).

Check: \(52 \times 43 = 2{,}080 + 156 = 2{,}236\). Any other arrangement with smaller tens digits gives a smaller product. The greatest product is 2,236.

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