
Written solutions to the chapter problems. Check each step, then correct yourself.
1 Name the fraction ★★★
- The bar has 8 equal parts, so each part is \(\dfrac{1}{8}\) of the bar.
- 5 parts are shaded: \(\dfrac{5}{8}\).
- The other \(8-5=3\) parts are not shaded: \(\dfrac{3}{8}\). Check: \(\dfrac{5}{8}+\dfrac{3}{8}=\dfrac{8}{8}=1\) whole bar.
2 Pizza slices ★★★
- One slice is \(\dfrac{1}{6}\) of the pizza.
- Maya ate \(1+2=3\) slices, which is \(\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}\).
- \(6-3=3\) slices are left, which is \(\dfrac{3}{6}\). Dividing the top and bottom by 3 gives \(\dfrac{3}{6}=\dfrac{1}{2}\), so half the pizza is left.
3 Fill in the missing number ★★★
- \(2\times 3=6\), so multiply the top by 3: \(\dfrac{1\times 3}{2\times 3}=\dfrac{3}{6}\).
- \(3\times 4=12\), so \(\dfrac{2\times 4}{3\times 4}=\dfrac{8}{12}\).
- \(5\times 2=10\), so \(\dfrac{3\times 2}{5\times 2}=\dfrac{6}{10}\).
- \(4\times 25=100\), so \(\dfrac{3\times 25}{4\times 25}=\dfrac{75}{100}\).
4 Name the points ★★★
- The line is cut into 6 equal lengths. A is 1 jump from 0: \(\dfrac{1}{6}\). B is 3 jumps: \(\dfrac{3}{6}\). C is 5 jumps: \(\dfrac{5}{6}\).
- Divide 3 and 6 by 3: \(\dfrac{3}{6}=\dfrac{1}{2}\). Point B is halfway between 0 and 1.
5 True or false? ★★★
- True. Divide the top and bottom of \(\dfrac{2}{4}\) by 2 to get \(\dfrac{1}{2}\).
- False. \(\dfrac{3}{6}=\dfrac{1}{2}\), not \(\dfrac{1}{3}\). Three sixths is half of the whole.
- True. \(\dfrac{4\div 2}{10\div 2}=\dfrac{2}{5}\).
- False. \(\dfrac{2}{3}=\dfrac{8}{12}\) and \(\dfrac{3}{4}=\dfrac{9}{12}\), and \(8\ne 9\).
6 Same denominator or same numerator ★★★
- Same denominator, and \(2\lt 4\): \(\dfrac{2}{5}\lt\dfrac{4}{5}\).
- Six sixths make one whole: \(\dfrac{6}{6}=1\).
- Same numerator. Thirds are bigger pieces than eighths, so \(\dfrac{1}{3}\gt\dfrac{1}{8}\).
- Same denominator, and \(5\gt 3\): \(\dfrac{5}{8}\gt\dfrac{3}{8}\).
7 Above or below one half ★★★
Compare each numerator with half of its denominator.
- \(\dfrac{3}{8}\): half of 8 is 4 and \(3\lt 4\), so less than one half.
- \(\dfrac{5}{6}\): half of 6 is 3 and \(5\gt 3\), so greater.
- \(\dfrac{4}{8}\): half of 8 is 4, so equal to one half.
- \(\dfrac{2}{5}\): half of 5 is 2.5 and \(2\lt 2.5\), so less.
- \(\dfrac{7}{12}\): half of 12 is 6 and \(7\gt 6\), so greater.
- \(\dfrac{1}{10}\): half of 10 is 5 and \(1\lt 5\), so less.
Less: \(\dfrac{3}{8}\), \(\dfrac{2}{5}\), \(\dfrac{1}{10}\). Equal: \(\dfrac{4}{8}\). Greater: \(\dfrac{5}{6}\), \(\dfrac{7}{12}\).
8 Two equivalent fractions ★★★
- \(\dfrac{3\times 2}{4\times 2}=\dfrac{6}{8}\) and \(\dfrac{3\times 3}{4\times 3}=\dfrac{9}{12}\).
- \(\dfrac{2\times 2}{5\times 2}=\dfrac{4}{10}\) and \(\dfrac{2\times 20}{5\times 20}=\dfrac{40}{100}\).
9 Simplify ★★★
- Divide by 2: \(\dfrac{3}{4}\).
- Divide by 2: \(\dfrac{5}{6}\). Only 1 divides both 5 and 6.
- Divide by 4: \(\dfrac{2}{3}\) (or divide by 2 twice).
- Divide by 25: \(\dfrac{1}{4}\).
10 Oatmeal scoops ★★★
Write \(\dfrac{2}{3}\) in sixths: \(\dfrac{2}{3}=\dfrac{2\times 2}{3\times 2}=\dfrac{4}{6}\). That is 4 copies of \(\dfrac{1}{6}\), so Lena needs 4 scoops.
For \(\dfrac{1}{3}=\dfrac{2}{6}\) she needs 2 scoops.
11 Fractions with unlike denominators ★★★
- Twelfths: \(\dfrac{8}{12}\) and \(\dfrac{9}{12}\). Since \(8\lt 9\): \(\dfrac{2}{3}\lt\dfrac{3}{4}\).
- Tenths: \(\dfrac{6}{10}\) and \(\dfrac{7}{10}\). Since \(6\lt 7\): \(\dfrac{3}{5}\lt\dfrac{7}{10}\).
- Twelfths: \(\dfrac{10}{12}\) and \(\dfrac{9}{12}\). Since \(10\gt 9\): \(\dfrac{5}{6}\gt\dfrac{3}{4}\).
- Eighths: \(\dfrac{3}{8}\) and \(\dfrac{2}{8}\). Since \(3\gt 2\): \(\dfrac{3}{8}\gt\dfrac{1}{4}\).
12 Two number lines ★★★
- A is \(\dfrac{1}{4}\), B is \(\dfrac{3}{4}\), C is \(\dfrac{2}{8}\), D is \(\dfrac{5}{8}\).
- A and C are at the same place: \(\dfrac{1}{4}=\dfrac{2}{8}\).
- B is at \(\dfrac{3}{4}=\dfrac{6}{8}\). D at \(\dfrac{5}{8}\) is to the left of B, so \(\dfrac{5}{8}\lt\dfrac{3}{4}\).
13 Who ran farther? ★★★
Use eighths: \(\dfrac{3}{4}=\dfrac{6}{8}\). Compare \(\dfrac{6}{8}\) and \(\dfrac{5}{8}\): \(6\gt 5\).
Leo ran farther, by \(\dfrac{6}{8}-\dfrac{5}{8}=\dfrac{1}{8}\) of a mile.
14 Least to greatest ★★★
Use sixths: \(\dfrac{1}{2}=\dfrac{3}{6}\), \(\dfrac{1}{3}=\dfrac{2}{6}\), \(\dfrac{1}{6}\), \(\dfrac{5}{6}\).
The numerators in order are 1, 2, 3, 5, so \(\dfrac{1}{6}\lt\dfrac{1}{3}\lt\dfrac{1}{2}\lt\dfrac{5}{6}\).
15 Find the unknown number ★★★
- \(5\times 20=100\), so \(4\times 20=80\): \(\dfrac{80}{100}\).
- \(12\div 3=4\), so \(9\div 3=3\): \(\dfrac{3}{4}\).
- \(3\times 3=9\), so \(8\times 3=24\): \(\dfrac{9}{24}\).
- \(7\times 3=21\), so \(10\times 3=30\): \(\dfrac{21}{30}\).
16 Find the mistake ★★★
Ben is wrong. Adding the same number to the top and bottom does not keep the amount. The rule needs multiplying or dividing.
A correct fraction: \(\dfrac{2\times 2}{3\times 2}=\dfrac{4}{6}\).
To compare, use fifteenths: \(\dfrac{2}{3}=\dfrac{10}{15}\) and \(\dfrac{4}{5}=\dfrac{12}{15}\). Since \(12\gt 10\), \(\dfrac{4}{5}\gt\dfrac{2}{3}\), so they are not equal.
17 Which equal one half? ★★★
A fraction equals \(\dfrac{1}{2}\) when the denominator is twice the numerator.
- \(\dfrac{5}{10}\): \(2\times 5=10\), equal.
- \(\dfrac{6}{12}\): \(2\times 6=12\), equal.
- \(\dfrac{50}{100}\): \(2\times 50=100\), equal.
- \(\dfrac{4}{9}\): \(2\times 4=8\lt 9\), so \(\dfrac{4}{9}\lt\dfrac{1}{2}\).
- \(\dfrac{3}{5}\): \(2\times 3=6\gt 5\), so \(\dfrac{3}{5}\gt\dfrac{1}{2}\).
18 Ribbons for a craft ★★★
- Use twelfths: red \(=\dfrac{10}{12}\), blue \(=\dfrac{9}{12}\), green \(=\dfrac{7}{12}\). Since \(7\lt 9\lt 10\): green, then blue, then red. That is \(\dfrac{7}{12}\lt\dfrac{3}{4}\lt\dfrac{5}{6}\).
- \(\dfrac{2}{3}=\dfrac{8}{12}\). Red (10) and blue (9) are greater than 8, but green (7) is not. The red and blue ribbons are longer than \(\dfrac{2}{3}\) yard.
19 Same numerator ★★★
Both fractions count 3 pieces. Fifths are bigger pieces than eighths because the whole is cut into fewer parts. Three big pieces are more than three small ones, so \(\dfrac{3}{5}\gt\dfrac{3}{8}\).
The numerator is always 7. The bigger the denominator, the smaller the pieces, so the order is \(\dfrac{7}{12}\lt\dfrac{7}{10}\lt\dfrac{7}{8}\).
20 Phone batteries ★★★
Use tenths: A is \(\dfrac{4}{10}\); B is \(\dfrac{3\times 2}{5\times 2}=\dfrac{6}{10}\); C is \(\dfrac{1\times 5}{2\times 5}=\dfrac{5}{10}\).
Since \(4\lt 5\lt 6\), the order is A, then C, then B. Phone B has the most charge.
21 Vegetable garden ★★★
- Peppers: \(\dfrac{1}{2}=\dfrac{5}{10}\), the greatest of 4, 5 and 1 tenths.
- \(\dfrac{4}{10}\lt\dfrac{1}{2}\), because \(\dfrac{4}{10}\lt\dfrac{5}{10}\).
- \(1-\dfrac{5}{10}=\dfrac{5}{10}=\dfrac{1}{2}\).
- \(\dfrac{4}{10}+\dfrac{5}{10}+\dfrac{1}{10}=\dfrac{10}{10}=1\), so the whole garden is used.
22 Fractions in between ★★★
- \(\dfrac{1}{2}=\dfrac{4}{8}\) and \(1=\dfrac{8}{8}\). The numerators between 4 and 8 are 5, 6 and 7: \(\dfrac{5}{8}\), \(\dfrac{6}{8}\), \(\dfrac{7}{8}\).
- \(\dfrac{1}{3}=\dfrac{4}{12}\) and \(\dfrac{2}{3}=\dfrac{8}{12}\). The numerators between 4 and 8 are 5, 6 and 7: \(\dfrac{5}{12}\), \(\dfrac{6}{12}\), \(\dfrac{7}{12}\).
Test yourself: quick challenge for Grade 4
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