
A puzzle with a missing number, a scale that must stay balanced, a speed limit you cannot go over: all of these are about equations and inequalities. In this chapter you will learn to use a letter for an unknown number, to find the value that makes an equation true, to turn a story into an equation, and to describe a whole group of numbers with an inequality.
1. Variables as unknowns
A variable is a letter (such as \(x\), \(n\) or \(p\)) that stands for a number. Sometimes the number is unknown: you are trying to find it. Sometimes the variable can take many different values. In this chapter we mostly use a variable as an unknown.
In algebra we do not write the multiplication sign next to a letter: \(5n\) means \(5 \times n\), and \(\dfrac{n}{4}\) means \(n \div 4\).
An expression such as \(x + 7\) or \(3n\) is a calculation that contains a variable. An equation is a statement with an equal sign, such as \(x + 7 = 12\). It says that two expressions have the same value.
2. Solutions of equations
A solution of an equation is a value of the variable that makes the equation true. To test a value, substitute it for the letter and compute both sides.
Is \(x = 8\) a solution of \(x + 14 = 22\)? Substitute: \(8 + 14 = 22\). Both sides are equal, so yes, 8 is a solution.
Is \(n = 5\) a solution of \(4n = 24\)? Substitute: \(4 \times 5 = 20\), and \(20 \neq 24\). So no, 5 is not a solution.
The equal sign does not mean “here comes the answer”. It means that the left side and the right side have the same value.
3. One-step equations: adding and subtracting
Think of an equation as a balance scale. If the two pans hold the same weight, the scale is level. To keep it level, whatever you do to one pan you must do to the other.
On the scale, remove 5 units from each pan. The box \(x\) is left alone on one side, and 7 units remain on the other: \(x = 7\).
- Find the operation that is applied to the variable.
- Do the inverse operation on both sides: subtraction undoes addition, addition undoes subtraction, division undoes multiplication, multiplication undoes division.
- Write the solution, then check it by substituting.
Solve \(x + 14 = 33\). Subtract 14 from both sides: \(x + 14 - 14 = 33 - 14\), so \(x = 19\). Check: \(19 + 14 = 33\). Correct.
Solve \(y - 6 = 11\). Add 6 to both sides: \(y = 11 + 6 = 17\). Check: \(17 - 6 = 11\). Correct.
4. One-step equations: multiplying and dividing
When the variable is multiplied by a number, divide both sides by that number. When it is divided by a number, multiply both sides by that number.
Solve \(8m = 56\). Divide both sides by 8: \(m = 56 \div 8 = 7\).
Solve \(\dfrac{z}{4} = 9\). Multiply both sides by 4: \(z = 9 \times 4 = 36\). Check: \(36 \div 4 = 9\).
Solve \(1.5k = 6\). Divide both sides by 1.5: \(k = 4\). Check: \(1.5 \times 4 = 6\).
On my planet we always finish with a check. Put your answer back into the original equation: if both sides match, you can trust it!
5. Writing equations from word problems
To turn a story into an equation, choose a letter for the unknown, find the key words, and write the relationship.
- “more than”, “total”, “increased by” suggest addition;
- “less than”, “left”, “decreased by” suggest subtraction;
- “times”, “each”, “equal groups” suggest multiplication;
- “shared equally”, “split into” suggest division.
A tape diagram helps: here three equal boxes hold 36 crayons in all, so \(3x = 36\) and \(x = 12\) crayons per box.
Lena had some marbles. She won 15 more and now has 42. Let \(m\) be the number she had at first. Equation: \(m + 15 = 42\). Subtract 15: \(m = 27\). Answer: she had 27 marbles at first.
“7 less than a number” is written \(n - 7\), not \(7 - n\). The order matters for subtraction.
6. Inequalities on a number line
An inequality compares two quantities that may be different. The symbols are \(<\) (less than), \(>\) (greater than), \(\leq\) (less than or equal to) and \(\geq\) (greater than or equal to).
An inequality such as \(x > 3\) has infinitely many solutions: 3.1, 4, 7.5, 100, and so on. We show them all on a number line. An open circle means the endpoint is not included (\(<\) or \(>\)). A closed circle means it is included (\(\leq\) or \(\geq\)). The shaded ray points toward the solutions.
Here 3 is not a solution (open circle), but 4 is.
Here 6 is a solution (closed circle), and so are 5, 2.5 and 0.
7. Solving one-step inequalities
Solving an inequality works like solving an equation: use the inverse operation on both sides. With positive numbers, the direction of the symbol does not change.
Solve \(x + 9 > 20\). Subtract 9 from both sides: \(x > 11\).
Solve \(5n \leq 35\). Divide both sides by 5: \(n \leq 7\). Check with 7: \(5 \times 7 = 35 \leq 35\), true. Check with 10: \(50 \leq 35\) is false, so 10 is outside the solution set.
If you add or subtract the same number on both sides of an inequality, or multiply or divide both sides by the same positive number, the solutions stay the same.
8. Writing inequalities from context
Some words tell you which symbol to use.
| Words | Symbol |
|---|---|
| more than, greater than, over | \(>\) |
| less than, fewer than, under | \(<\) |
| at least, no less than, minimum | \(\geq\) |
| at most, no more than, maximum | \(\leq\) |
A bridge allows trucks that weigh at most 8 tons. Let \(w\) be a truck’s weight in tons: \(w \leq 8\). A truck of 7.5 tons may cross; one of 8.2 tons may not.
Nora has $30 and wants a game that costs at least $45. She must save \(s\) more dollars: \(30 + s \geq 45\), so \(s \geq 15\). She needs to save at least $15.
Key takeaways
- A variable is a letter that stands for a number; a solution makes an equation true.
- To solve a one-step equation, use the inverse operation on both sides, then check.
- To write an equation, name the unknown and translate the key words.
- An inequality has many solutions; an open circle excludes the endpoint and a closed circle includes it.
- “At least” means \(\geq\) and “at most” means \(\leq\).
- With positive numbers, solve an inequality exactly like an equation.
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