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Proportional Relationships and Slope: practice solutions, Grade 8 – download the PDF

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Practice solutions Grade 8 : Proportional Relationships and Slope — Zyro the alien explorer of Planète Maths

Written solutions to the chapter problems. Check each step, then correct yourself.

2 Smoothie prices ★★★

Price per cup: \(\dfrac{10}{4} = 2.50\) dollars, so \(y = 2.5x\).

Cups \(x\) 1 2 5 8
Cost \(y\) ($) 2.50 5.00 12.50 20.00

Check: \(2.5 \times 8 = 20\).

3 Proportional or not? ★★★

  1. The ratios \(\dfrac{6}{2}, \dfrac{12}{4}, \dfrac{15}{5}\) all equal 3. Yes, proportional, with \(y = 3x\).
  2. The ratios are \(\dfrac{3}{1} = 3\), \(\dfrac{5}{2} = 2.5\), \(\dfrac{7}{3} \approx 2.33\). They are not equal, so no, not proportional.

4 Reading a slope ★★★

From \(A\) to \(B\): run \(= 6 - 2 = 4\), rise \(= 9 - 3 = 6\).

\(m = \dfrac{6}{4} = \dfrac{3}{2} = 1.5\).

Answer: the slope is 1.5.

5 Two points ★★★

\(m = \dfrac{11 - 2}{4 - 1} = \dfrac{9}{3} = 3\).

Answer: the slope is 3.

6 Highway speed ★★★

\(\dfrac{150}{2.5} = 60\) miles per hour.

\(60 \times 1.609 \approx 96.5\), so about 96.5 kilometers per hour.

7 Plotting y = 2x ★★★

The pairs are \((0, 0), (1, 2), (2, 4), (3, 6)\).

123412345678O(1, 2)(2, 4)(3, 6)

The points line up on a line through the origin. Each step of 1 to the right raises \(y\) by 2, so the slope is 2, equal to the coefficient of \(x\).

8 A steep negative slope ★★★

\(m = \dfrac{-8 - 4}{5 - (-3)} = \dfrac{-12}{8} = -\dfrac{3}{2}\).

The slope is negative, so the line falls from left to right: \(-1.5\) units in \(y\) for each unit in \(x\).

9 Horizontal and vertical ★★★

  1. \(m = \dfrac{5 - 5}{7 - 2} = \dfrac{0}{5} = 0\): a horizontal line.
  2. \(m = \dfrac{6 - (-1)}{3 - 3} = \dfrac{7}{0}\): division by zero, so the slope is undefined (a vertical line).

10 Apple prices ★★★

  1. Store A: \(\dfrac{9}{5} = 1.80\) dollars per pound. Store B: 1.95 dollars per pound. Since \(1.80 < 1.95\), Store A is cheaper.
  2. Store A: \(12 \times 1.80 = 21.60\). Store B: \(12 \times 1.95 = 23.40\). Savings: \(23.40 - 21.60 = 1.80\) dollars.

11 A draining tank ★★★

  1. \(m = \dfrac{36 - 60}{8 - 0} = \dfrac{-24}{8} = -3\). The tank loses 3 gallons every minute.
  2. No. The line does not pass through the origin (it starts at 60), and the ratio \(\dfrac{y}{x}\) is not constant (for example \(\dfrac{36}{8} = 4.5\)).
  3. Draining 60 gallons at 3 gallons per minute takes \(\dfrac{60}{3} = 20\) minutes.

12 A missing coordinate ★★★

Slope: \(\dfrac{10}{4} = 2.5\), so \(y = 2.5x\).

For \(x = 6\): \(k = 2.5 \times 6 = 15\).

Check with the slope: \(\dfrac{15 - 10}{6 - 4} = \dfrac{5}{2} = 2.5\).

13 Equation from a table ★★★

\(\dfrac{7}{2} = 3.5\), \(\dfrac{17.5}{5} = 3.5\), \(\dfrac{31.5}{9} = 3.5\). The ratio is constant.

Answer: \(k = 3.5\) and \(y = 3.5x\).

14 Running pace ★★★

40 minutes \(= \dfrac{2}{3}\) hour, so \(\dfrac{6}{2/3} = 6 \times \dfrac{3}{2} = 9\) kilometers per hour.

\(\dfrac{9}{1.609} \approx 5.6\) miles per hour.

15 Similar triangles on a line ★★★

  1. Small: \(\dfrac{3}{4} = 0.75\). Large: \(\dfrac{9}{12} = \dfrac{3}{4} = 0.75\). The triangles are similar (same angles, sides scaled by 3), so the ratio is the same.
  2. \(\text{rise} = 20 \times \dfrac{3}{4} = 15\).

16 Wheelchair ramp ★★★

  1. \(m = \dfrac{2.5}{30} = \dfrac{1}{12}\).
  2. \(\dfrac{1.5}{\text{run}} = \dfrac{1}{12}\), so run \(= 1.5 \times 12 = 18\) feet.

17 Find the unknown ★★★

\(\dfrac{13 - k}{6 - 2} = 2.5\), so \(13 - k = 10\), which gives \(k = 3\).

Check: \(\dfrac{13 - 3}{4} = 2.5\).

18 Two sprinklers ★★★

  1. Sprinkler 1: \(\dfrac{8}{5} = 1.6\). Sprinkler 2: 1.7. Since \(1.7 > 1.6\), Sprinkler 2 has the steeper line and the greater rate.
  2. Sprinkler 1: \(1.6 \times 20 = 32\) gallons. Sprinkler 2: \(1.7 \times 20 = 34\) gallons.

19 Collinear points ★★★

  1. Slope of \(AB\): \(\dfrac{4 - (-2)}{2 - (-1)} = \dfrac{6}{3} = 2\). Slope of \(BC\): \(\dfrac{10 - 4}{5 - 2} = \dfrac{6}{3} = 2\). The slopes match and \(B\) is shared, so the three points are on one line, \(y = 2x\).
  2. Slope of \(CD\): \(\dfrac{15 - 10}{8 - 5} = \dfrac{5}{3} \neq 2\). Equivalently, \(2 \times 8 = 16 \neq 15\). So \(D\) is not on the line.

20 Find the error ★★★

The student put the run (change in \(x\)) on top and the rise (change in \(y\)) on the bottom. Slope is rise over run.

Correct: \(m = \dfrac{11 - 3}{5 - 1} = \dfrac{8}{4} = 2\).

21 Two printers ★★★

Printer A: \(\dfrac{90}{6} = 15\) pages per minute. Printer B: \(\dfrac{64}{4} = 16\) pages per minute.

Together: \(15 + 16 = 31\) pages per minute.

Time: \(\dfrac{465}{31} = 15\) minutes.

Back to the practice problems : Proportional Relationships and Slope: practice solutions, Grade 8 – Planète MathsTake the quiz : Proportional Relationships and Slope: practice solutions, Grade 8 – Planète MathsTake the test : Proportional Relationships and Slope: practice solutions, Grade 8 – Planète Maths

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